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Fundamental Laws of Logarithms

The antilog o...

Question

The antilog of $\frac{2}{5}$ to the base $243$ is

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Solution

Antilog of $\frac{2}{5}$ to the base $243$ is
$(243)^{2 / 5} = (3^{5})^{2 / 5} = 3^{2} = 9$

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Fundamental Laws of Logarithms

Standard XI Mathematics

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