The apparent frequency of the whistle of an engine changes in the ratio of 6:5 as the engine passes a stationary observer. If the velocity of sound is 330 m/s, then the velocity of the engine is

3 m/s

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30 m/s

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0.33 m/s

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660 m/s

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Solution

The correct option is B 30 m/s
$v^{'} = \frac{v}{v - v_{s}} v, v "= \frac{v}{v + v_{s}} v \frac{v^{'}}{v^{''}} = \frac{v + v_{z}}{v - v_{s}} o r \frac{6}{5} = \frac{330 + v}{330 - v} 11 v_{s} = 330 \Rightarrow v_{s} = 30 m / s$

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The apparent frequency of the whistle of an engine changes in the ratio of 6:5 as the engine passes a stationary observer. If the velocity of sound is 330 m/s, then the velocity of the engine is

The correct option is B 30 m/sv′=vv−vsv, v"=vv+vsvv′v′′=v+vzv−vs or 65=330+v330−v11vs=330 ⇒ vs=30 m/s

The correct option is B 30 m/s
$v^{'} = \frac{v}{v - v_{s}} v, v "= \frac{v}{v + v_{s}} v \frac{v^{'}}{v^{''}} = \frac{v + v_{z}}{v - v_{s}} o r \frac{6}{5} = \frac{330 + v}{330 - v} 11 v_{s} = 330 \Rightarrow v_{s} = 30 m / s$