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the applied p...

Question

the applied potential difference across a given resistor is altered so that the heat produced per second increases by factor of 16 . by what factor the applied potential difference changes.

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Solution

$H e a t g e n e r a t e d, H = I^{2} R t = \frac{V^{2} t}{R} \frac{H}{H'} = \frac{V^{2}}{V'^{2}} = \frac{1}{16} V'^{2} = 16 V^{2} V' = 4 V S o t h e p o t e n t i a l w i l l i n c r e a s e b y a f a c t o r 4 .$

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