The approximate phase response of 1002e-0-01ss2-0-2s-1002 is

TF=100^2e^ 0.01ss^2+0.2s+100^2 Here, phase of 100^2s^2+0.2s+100^2 varies from 0^o to 180^o as ω→∞, therefore e^ 0.01s causes further phase lag, hence the c ...

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The approximate phase response of $\frac{100^{2} e^{- 0.01 s}}{s^{2} + 0.2 s + 100^{2}} i s$

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Solution

The correct option is A
$T F = \frac{100^{2} e^{- 0.01 s}}{s^{2} + 0.2 s + 100^{2}}$
Here, phase of
$\frac{100^{2}}{s^{2} + 0.2 s + 100^{2}}$ varies from
$0^{o} t o - 180^{o} a s ω \to \infty, t h e r e f o r e e^{- 0.01 s}$ causes further phase lag, hence the correct answer is (a).

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The approximate phase response of 1002e−0.01ss2+0.2s+1002is

The correct option is A TF=1002e−0.01ss2+0.2s+1002 Here, phase of 1002s2+0.2s+1002 varies from 0o to −180o as ω→∞, therefore e−0.01s causes further phase lag, hence the correct answer is (a).

The approximate phase response of $\frac{100^{2} e^{- 0.01 s}}{s^{2} + 0.2 s + 100^{2}} i s$

The correct option is A
$T F = \frac{100^{2} e^{- 0.01 s}}{s^{2} + 0.2 s + 100^{2}}$
Here, phase of
$\frac{100^{2}}{s^{2} + 0.2 s + 100^{2}}$ varies from
$0^{o} t o - 180^{o} a s ω \to \infty, t h e r e f o r e e^{- 0.01 s}$ causes further phase lag, hence the correct answer is (a).