Question

The approximate size of the nucleus of ${}_{28}^{64}Ni$ is:

• A. 3 fm
• B. 4 fm
• C. 5 fm
• D. 2 fm

Answer 1

Answer: (C)

5 fm

Approximate size of the nucleus is given by,

$R_A=1.25\times A^{\frac{1}{3}}fm$, for this given nucleus $A=64$, and $Z=28$,

Therefore size of this nucleus,

$R_{64}=1.25\times {64}^{\frac{1}{3}}fm=5.0fm$

So, option 'C' is correct.