The approximate value of $(1.01)^{- 7}$ is

0.3

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0.7

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0.49

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0.93

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Solution

The correct option is B $0.93$
The approximate value of ${(1 + x)}^{n}$ for $x < 1$ is $1 + n x$
So, ${(1 + 0.01)}^{- 7}$ as $0.01 < 1$
$1 +$ $(- 7) \times (0.01)$ $=$ $1 - 0.07 = 0.93$
Thus approximate value of $(1.01)^{- 7}$ is $0.93$ .

Suggest Corrections

Similar questions

{cos}^{- 1} (- 0.49)

\sqrt{(0.49)} = x,

x =

(0.7)^{3} + (0.3)^{3} + 3 \times 0.7 \times 0.3 (0.7 + 0.3)

\sqrt{49} = 7

\sqrt{49} + \sqrt{0.49} + \sqrt{0.0049} + \sqrt{0.000049}

3^{7} = 7^{x}

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