Question

The approximate value of ${\int }_1^2\frac{dx}{1+x}$ with $n=2$ is

• A. $0.408$
• B. $0.412$
• C. $0.321$
• D. $0.318$

Answer 1

The correct option is A $0.408$

$f\left(x\right)=1/(1+x),h=1/2,x_0=1,y_0=1/2,y_1=2/5,y_2=1/3$
$\therefore {\int }_0^2\frac{dx}{1+x}=\frac{1}{2}\left(\frac{1}{2}\right(y_0+y_2)+y_1)=\mathrm{0.408.}$