Question

the approximate wavelength associated with a gold ball weighing 200g and moving at a speed of 5km/hr is order of

Answer 1

According to de-Broglie wavelength,
$$\begin{gathered} \lambda =\frac{h}{mV} \\ h=planck\text{'}scons\tan t=6.626\times {10}^{-34}J-s \\ m=200\times {10}^{-3}kg \\ V=5km/hr=\frac{5\times {10}^3}{60\times 60}m/sec \\ Wavelength,\lambda \\ =\frac{6.626\times {10}^{-34}\times 60\times 60}{200\times {10}^{-3}\times 5\times {10}^3} \\ =23.85\times {10}^{-34}m \end{gathered}$$