The approximate wavelength of a photon of energy $2.48$ eV is

500 ˚ A

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5000 ˚ A

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2000 ˚ A

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1000 ˚ A

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Solution

The correct option is B $5000 ˚ A$
We know that,
$E (e V) = \frac{12375}{λ 0 A}$
$\Rightarrow λ = \frac{12375}{(2.48)}$
$λ = 4989.9 0 A \approx 5000 0 A$
Approximate wavelength of a photon of energy $2.48 e V = 5000 0 A$ .

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The approximate wavelength of a photon of energy 2.48 eV is

The correct option is B 5000˚AWe know that,E(eV)=12375λ0A⇒λ=12375(2.48)λ=4989.90A≈50000AApproximate wavelength of a photon of energy 2.48eV=50000A.

The approximate wavelength of a photon of energy $2.48$ eV is

The correct option is B $5000 ˚ A$
We know that,
$E (e V) = \frac{12375}{λ 0 A}$
$\Rightarrow λ = \frac{12375}{(2.48)}$
$λ = 4989.9 0 A \approx 5000 0 A$
Approximate wavelength of a photon of energy $2.48 e V = 5000 0 A$ .