Question

The aqueous solution having pH 11 is how many times less basic the aqueous solution having pH 8?

• A. 8
• B. 30
• C. 300
• D. 1000

Answer 1

The correct option is D 1000

For aqueous $so{l}^n$ of $pH=8$,

we have,

$\left[H^{+}\right]={10}^{-8}$

For aqueous $so{l}^n$ of $pH=11$,

we have,

$\left[H^{+}\right]={10}^{-11}$

So, $\frac{{10}^{-8}}{{10}^{-11}}={10}^{+3}=1000$ times less $H^{+}$ ions and thus $so{l}^n$ with $pH$ $11$ is $1000$ times less basic than the aqueous $so{l}^n$ having $pH$ $8$