The aqueous solution of 'A' is alkaline due to

the presence of

C a^{2 +}

ions

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the presence of

H_{3} B O_{3}

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hydrolysis of

B_{4} O_{7}^{2 -}

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hydrolysis of

C O_{3}^{2 -}

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Solution

The correct option is C hydrolysis of $B_{4} O_{7}^{2 -}$
A is borax or sodium tetraborate $(N a_{2} B_{4} O_{7} .10 H_{2} O)$ .

One mole of A contains 10 moles of water of crystallization.

It is a white crystalline solid and is used in water softening. Its aqueous solution is alkaline due to the formation of sodium hydroxide upon hydrolysis of $N a_{2} B_{4} O_{7}$ . The reaction is as follows:

$N a_{2} B_{4} O_{7} + 7 H_{2} O ⇌ 2 N a O H + 4 H_{3} B O_{3}$

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Similar questions

C H_{3} C O O N a

Option	(a)	(b)	(c)	(d)
(1)	Acidic Hydrolysis	$N H_{3}$ and $N H_{4} B F_{4}$	Hydrolysis	Heating only
(2)	Acidic Hydrolysis	$N H_{4} B F_{4}$	Hydrolysis	Heating in presence of $M g o r F e$
(3)	Alkaline Hydrolysis	$N H_{4} B F_{4}$	Hydrolysis	Heating only
(4)	Alkaline Hydrolysis	$N_{2} + B F_{3}$	Hydrolysis	Heating in presence of $M g o r F e$

N a_{2} C O_{3}

C u S O_{4} .5 H_{2} O

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