The arc of a circle of radius $21 c m$ subtends an angles of $60^{o}$ at the center, find the length of the arc.(in cm) (Take $π = 22 / 7$ ).

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Solution

Give $R = 21 c m$ , $θ = \frac{π}{3}$
We have,
$l = R Q$
$∴ l = 21 \times \frac{π}{3} = 7 π = 7 \times \frac{π}{7} = 22 c m$
$∴$ Length of Arc $= 22 c m$

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The arc of a circle of radius 21cm subtends an angles of 60o at the center, find the length of the arc.(in cm) (Take π=22/7).

Give R=21cm, θ=π3We have,l=RQ∴l=21×π3=7π=7×π7=22cm∴ Length of Arc =22cm

The arc of a circle of radius $21 c m$ subtends an angles of $60^{o}$ at the center, find the length of the arc.(in cm) (Take $π = 22 / 7$ ).

Give $R = 21 c m$ , $θ = \frac{π}{3}$
We have,
$l = R Q$
$∴ l = 21 \times \frac{π}{3} = 7 π = 7 \times \frac{π}{7} = 22 c m$
$∴$ Length of Arc $= 22 c m$