Question

The are of $△ABC$ with vertices A(3, 0), B(7, 0) and C(8, 4) is

(a) 14 sq units (b) 28 sq units (c) 8 sq units (d) 6 sq units

Answer 1

Area $=\frac{1}{2}\left[3\right(0-4)+7(4-0)+8(0-0\left)\right]$

$=\frac{1}{2}\times 16=8units$

So, the correct choice is (c).