The correct option is
B 12
Total area available to anchor tents = 132.66 sq ft
Area of type A section = 3 sq ft
Area of type B section = 2.5 sq ft
Now, 1 tent consists of two units of each type of section.
Area of 1 tent = (2 × Area of type A section) + (2 × Area of type B section)
Area of 1 tent = (2 × 3 sq ft) + (2 × 2.5 sq ft)
Area of 1 tent = 6 sq ft + 5 sq ft = 11 sq ft
Divide the available area with the area occupied by one tent, which is 11 sq ft, to find the number of tents.
Dividend = 132.66
Divisor = 11
Division equation
132.66 ÷ 11 = ?
The answer is 12.06. Since we cannot anchor a fractional number of tents, we need to round off the number to the smaller whole number, not the nearest whole. However, in this case, the smallest whole number is also the nearest whole.
Rounding 12.06 to the smallest whole gives 12. So, 12 tents can be anchored.
Hence, option B is correct.