Question

The area between the curve $y^2=9x$ and the line $y=3x$ is

• A. $\frac{1}{3}$ sq units
• B. $\frac{8}{3}$ sq. units
• C. $\frac{1}{2}$ sq. units
• D. $\frac{1}{5}$ sq. units

Answer 1

Answer: (C)

$\frac{1}{2}$ sq. units

R.E.F image

$y=3x$

$y^2=a{x}^2$

$ax=a{x}^2$

$x=0,x=1$

Area bounded $={\int }_0^1(3\sqrt{x}-3x)dx$

$=[\frac{32x^{3/2}}{3}-\frac{3x^2}{2}{]}_0^1$

$=2-\frac{3}{2}=1/2$ sq.units