Question

The area between the curve $y=x^2$ and $y=x+2$ is:

• A. $\frac{9}{2}$ sq. units
• B. $\frac{3}{2}$ sq. units
• C. 9 sq. units
• D. 6 sq. units

Answer 1

Answer: (A)

$\frac{9}{2}$ sq. units

point of intersection $x^2-x-2=0$
2,-1
$\stackrel{2}{\underset{-1}{\int }}(x+2)dx-\stackrel{2}{\underset{-1}{\int }}{x}^{2}dx$
$3/2+2\left(3\right)-[\frac{8}{3}+1/3]$
$3/2+6-3$
$6-3/2=9/2squnits$