Question

The area between the parabola $y^2=4x$, normal at one end of latus rectum and $x-axis$ in sq. units is:

• A. $\frac{1}{3}$
• B. $\frac{2}{3}$
• C. $\frac{10}{3}$
• D. $\frac{4}{3}$

Answer 1

The correct option is D $\frac{4}{3}$

R.E.F image

$y^2=4x$

area = ?

$2\int \sqrt{x}=2\times 2(x{)}^{3/2}$

$=\frac{4}{3}\left(1\right)$