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Standard X

Mathematics

Areas of Combination of Plane figures

The area betw...

Question

The area between two concentric circles of radii $r_{1}$ and $r_{2},$ is equal to [ $r_{2} > r_{1}$ ]

zero

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π r_{1}^{2}

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π r_{2}^{2}

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πr22-πr12

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Solution

The correct option is D πr22-πr12
The area between two concentric circles is shaded in blue as shown in the figure:
Area of the shaded region $=$ Area of bigger circle $-$ Area of smaller circle.
$= π r_{2}^{2} - π r_{1}^{2}$

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Similar questions

Q. If the sum of the areas of two circles with radii

r_{1}

and

r_{2}

is equal to the area of circle of radius

r

, then
(a)

r = r_{1} + r_{2}

(b)

{r_{1}}^{2} + {r_{2}}^{2} = r^{2}

(c)

r_{1} + r_{2} < r

(d)

{r_{1}}^{2} + {r_{2}}^{2} < r^{2}

If the sum of the areas of two circles with radii $R_{1}$ and $R_{2}$ is equal to the area of a circle of radius R then

(a) $R_{1} + R_{2} = R$

(b) $R_{1} + R_{2} > R$

(d) $R_{1}^{2} + R_{2}^{2} = R^{2}$

Q. If the sum of the areas of two circles with radii R₁ and R₂ is equal to the area of a circle of radius R, then
(a)

R_{1} + R_{2} = R

(b)

R_{1} + R_{2} < R

(c)

R_{1}^{2} + R_{2}^{2} < R^{2}

(d)

R_{1}^{2} + R_{2}^{2} = R^{2}

Q. If the sum of the circumferences of two circles with radii R₁ and R₂ is equal to the circumference of a circle of radius R, then
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(b)

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(d) none of these

Q. Three circles of radii

r_{1}

r_{2}

and

r_{3}

are drawn concentric to each other. The radii

r_{1}

and

r_{2}

are such that the area of the circle with radius

r_{1}

is equal to the area between the circles of radii

r_{2}

and

r_{1}

. The area between the circles of radii

r_{3}

and

r_{2}

is equal to the area between the circles of radii

r_{2}

and

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What is the value of

r_{1} : r_{2} : r_{3}

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The area between two concentric circles of radii r1 and r2, is equal to [r2>r1]

The correct option is D πr22-πr12The area between two concentric circles is shaded in blue as shown in the figure: Area of the shaded region = Area of bigger circle − Area of smaller circle. =πr22−πr21

The area between two concentric circles of radii $r_{1}$ and $r_{2},$ is equal to [ $r_{2} > r_{1}$ ]

The correct option is D πr22-πr12
The area between two concentric circles is shaded in blue as shown in the figure:
Area of the shaded region $=$ Area of bigger circle $-$ Area of smaller circle.
$= π r_{2}^{2} - π r_{1}^{2}$