Question

The area bounded by $e^{ln(x+1)}\ge |y|,|x|\le 1$ is :

• A. $1sq.units$
• B. $2sq.units$
• C. $3sq.units$
• D. $4sq.units$

Answer 1

Answer: (B)

$2sq.units$

$\therefore e^{ln(x+1)}\ge |y|$

$\therefore (x+1)\ge |y|$

$\therefore x\ge |y|-1$

$\therefore$ Area bounded$=\int ydx$

$={\int }_{-1}^1(x+1)dx$

$={\frac{x^2}{2}+x|}_{-1}^1$

$=1-(-1)$

$=2$.