The area bounded by the closed curve whose equation is $x^{2} - 6 x + y^{2} + 8 y = 0$ is

12 π

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 π

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

36 π

No worries! We‘ve got your back. Try BYJU‘S free classes today!

48 π

No worries! We‘ve got your back. Try BYJU‘S free classes today!

cannot be determined

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $25 π$
Given equation is $x^{2} - 6 x + y^{2} + 8 y = 0$
$\Rightarrow {(x - 3)}^{2} + {(y + 4)}^{2} = 25$
The radius of the circle is $5$ .
Therefore, area of circle is $π r^{2} = 25 π$ .

Suggest Corrections

Similar questions

x^{2} + y^{2} - 6 x + 8 y = 0

x^{2} + y^{2} = 6 x + 7

3 y^{2} = 16 x

x^{2} + y^{2} \leq 2 a x

y^{2} \geq a x

, a > 0, x > 0, Y > 0

\frac{16}{3}

\frac{3}{16}

\frac{14}{3}

\frac{3}{14}

y^{2} = 8 x

x^{2} = 8 y

Join BYJU'S Learning Program