The area bounded by the curve $y = x^{3},$ the x-axis and the ordinates x=-2 and x=1 is

- 9

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- 15 / 4

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15 / 4

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17 / 4

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Solution

The correct option is D $17 / 4$
$y$ is $- i v e$ for $- 2 \leq x \leq 0, + i v e f o r 0 < x \leq 1$
$∴ A r e a = ∣ ∣ ∣ \int_{- 2}^{0} y d x ∣ ∣ ∣ + \int_{0}^{1} y d x$
$= | - 4 | + \frac{1}{4} = 4 + \frac{1}{4} = \frac{17}{4} .$

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The area bounded by the curve y=x3,the x-axis and the ordinates x=-2 and x=1 is

The correct option is D 17/4y is −ive for −2≤x≤0,+ivefor0<x≤1 ∴Area=∣∣∣∫0−2ydx∣∣∣+∫10ydx =|−4|+14=4+14=174.

The area bounded by the curve $y = x^{3},$ the x-axis and the ordinates x=-2 and x=1 is

The correct option is D $17 / 4$
$y$ is $- i v e$ for $- 2 \leq x \leq 0, + i v e f o r 0 < x \leq 1$
$∴ A r e a = ∣ ∣ ∣ \int_{- 2}^{0} y d x ∣ ∣ ∣ + \int_{0}^{1} y d x$
$= | - 4 | + \frac{1}{4} = 4 + \frac{1}{4} = \frac{17}{4} .$