wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The area bounded by the curve y = loge x and x-axis and the straight line x = e is

(a) e sq. units

(b) 1 sq. units

(c) 1−1e sq. units

(d) 1+1e sq. units

Open in App
Solution

(b) 1 sq. units



The point of intersection of the curve and the straight line is A(e, 1).
Therefore, the area of the required region ABC,
A=01x1-x2 dy where, x1=e and x2=ey=01e-eydy=ey-ey01=e1-e1-e0-e0=e-e+1=1 square unit

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area under the Curve
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon