Question

The area bounded by the curve $y=1+\frac{8}{x^2}$ with $X$-axis, $x=2$ and $x=4$ in sq. units is

• A. $4$
• B. $2$
• C. $1/2$
• D. $5$

Answer 1

The correct option is A $4$

$y=1+\frac{8}{x^2}$
from $x=2andx=4$
So, $\stackrel{4}{\underset{2}{\int }}ydx$
$=\stackrel{4}{\underset{2}{\int }}(1+8/x^2)dx$
$=|x-8/x{|}_2^4$
$=[4-\frac{8}{4}]-[2-\frac{8}{2}]$
$=4-2-2+4$
$=4squnits$.