You visited us 1 times! Enjoying our articles? Unlock Full Access!

Graphical Interpretation of Differentiability

The area boun...

Question

The area bounded by the curve $y = 3 cos x$ and $x - a x i s$ where $0 \leq x \leq \frac{π}{2}$ is ...........

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $3$
Area = $\int_{0}^{1 / 2} y d x$
$= \int_{0}^{1 / 2} 3 c o s x d x$
$= 3 s i n x |_{0}^{1 / 2}$
$= 3 u n i t s^{2}$

Suggest Corrections

Similar questions

y = sin 2 x, x = 0, x = π

y = \frac{1}{1 + {(tan x)}^{\sqrt{2}}}

x -

x = \frac{π}{6}

x = \frac{π}{3}

\frac{π}{12}

The area bounded by the curve, x-axis and the ordinates x = –1 and x = 1 is given by

[Hint: y = x² if x > 0 and y = –x² if x < 0]

A. 0

y = \frac{1}{1 + \sqrt{tan x}}

x

x = \frac{π}{6}

x = \frac{π}{3}

y = \sqrt{(sin [x] + [sin x])},

[.]

x = 1

x = \frac{π}{2}

x -

Join BYJU'S Learning Program