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Question

The area bounded by the curves y=(x1)2,y=(x+1)2 and y=14
  1. 13
  2. 23
  3. 14
  4. 15


Solution

The correct option is A 13

Point of intersection of y=(x1)2 and y=14 is (12,14) and (32,14)

The required area
=21/20((x1)214)dx=2[(x1)3314x]1/20=2[12418+13]=13

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