Question

The area bounded by the ellipse $3x^2+2y^2=6$ with the co-ordinate axes in sq. units is

• A. $\sqrt{6}\pi$
• B. $\sqrt{8}\pi$
• C. $\sqrt{12}\pi$
• D. $\sqrt{3}\pi$

Answer 1

The correct option is A $\sqrt{6}\pi$

$3x^2+2y^2=6$
$\to x^2/2+y^2/3=1$
So, the area of the ellipse is $\pi \left(\sqrt{2}\right)\left(\sqrt{3}\right)$
$=\pi \left(\sqrt{6}\right)squnits.$