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Question

The area bounded by the parabolas y2=4a(x+a) and y2=4a(xa) is

A
163a2 sq units
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B
83 sq units
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C
43a2 sq units
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D
None of these
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Solution

The correct option is A 163a2 sq units
y2=4a(x+a)

y=±4ax+4a2

As the area bounded by this curve is in -ve x quadrant . Therfore
y=4ax+4a2

Area bounded by this curve will be 0a4ax+4a2dx
Area bounded by this curve will be 83a2

Similarly , The area bounded by y2=4a(xa) curve will be
a04ax+4a2dx
Area = 83a2

thus , total bounded area will be 163a2



710394_668721_ans_24a5e2b400114059b96e5bbd503f2ff2.png

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