MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Expression 'T'

The area boun...

Question

The area bounded by $(y - 2)^{2} = x - 1$ the tangent to it at the point whose ordinate is 3 and the x – axis is (in sq.units)___

Open in App

Solution

$(y - 2)^{2} = x - 1, P = (2, 3) E q e . F o r t a n g e n t : x - 2 y + 4 = 0 A = \int_{0}^{3} [(y - 2)^{2} + 1] d y - \int_{0}^{3} (2 y - 4) d y = 9$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The area of the region bounded by the parabola

(y - 2)^{2} = (x - 1),

the tangent to it at the point whose ordinate is

3

x -

Q. The area of the figure bounded by the parabola

(y - 2)^{2} = x - 1

, the tangent to it at the point with the ordinate

x = 3

, and the x-axis is

Q. The area of the figure bounded by the parabola

{(y - 2)}^{2} = x - 1

, the tangent to it at the point with the ordinate

3

x

Q. The area(in sq.units) bounded by the curve

y = x^{3}, x -

axis and the two ordinates

x = - 2, x = 1

Q. The area of the region bounded by the parabola (y − 2)² = x − 1, the tangent to it at the point with the ordinate 3 and the x-axis is
(a) 3
(b) 6
(c) 7
(d) none of these

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Tangent to a Circle

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon