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Expression 'T'

The area boun...

Question

The area bounded by $(y - 2)^{2} = x - 1$ the tangent to it at the point whose ordinate is 3 and the x – axis is (in sq.units)___

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Solution

$(y - 2)^{2} = x - 1, P = (2, 3) E q e . F o r t a n g e n t : x - 2 y + 4 = 0 A = \int_{0}^{3} [(y - 2)^{2} + 1] d y - \int_{0}^{3} (2 y - 4) d y = 9$

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