The area bounded by y2-4ax and y-mx is a23 square units then m-

∫_0^4a/m^2(√(4ax) mx)dx=8a^2/3m^3=a^2/3 m=2 ...

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Area between x=g(y) and y Axis

The area boun...

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The area bounded by $y^{2} = 4 a x$ and $y = m x$ is $\frac{a^{2}}{3}$ square units then $m =$

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