Question

The area bounded by $y=3-|3-x|$ and $y=\frac{6}{|x+1|}$ is:

• A. $\frac{15}{2}-6$ ln 2 sq. units
• B. $\frac{13}{2}-3$ ln 2 sq. units
• C. $\frac{13}{2}-6$ ln 2 sq. units
• D. None of these

Answer 1

The correct option is C $\frac{13}{2}-6$ ln 2 sq. units

$Area={\int }_2^3(x-\frac{6}{x+1})dx+{\int }_3^5((6-x)-\frac{6}{x+1})dx=\frac{13}{2}-6ln2$ sq.units