The area bounded by $y = | x - 1 |, y = 0$ and $| x | = 2$

4

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5

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3

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2

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Solution

The correct option is C $5$
REF.Image
Area = $\frac{1}{2} \times 3 \times 3 \times + \frac{1}{2} \times 1 \times 1$
$= \frac{9}{2} + \frac{1}{2} = \frac{10}{2} = 5$

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y = - | x | + 3, x = 0, y = 0

x = 2,

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List-I	List-II
1. Area of region bounded by $y = 2 x - x^{2}$ and $x -$ axis	a. $\frac{1}{3}$
2. Area of the region ${(x, y) : x^{2} \leq y \leq \| x \|}$	b. $\frac{1}{2}$
3. Area bounded by $y = x$ and $y = x^{3}$	c. $\frac{2}{3}$
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y = 4 x^{2}, x = 0

y = 1, y = 4

List-I	List-II
1. Area of the region bounded by $y = \| 5 sin x \|$ from $x = 0$ to $x = 4 π$ and x-axis	a. 3/2
2. The area bounded by $y =$ cosx in $[0, 2 π]$ and the $X$ -axis	b. $\sqrt{2} - 1$
3. The area bounded by $y = s i n x, y = c o s x$ and the y-axis	c. 4
4. The area bounded by $y = c o s x, y = x + 1, y = 0$	d. 40

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