The area bounded by $y = | x - 1 |, y = 0$ and $| x | = 2$ is

4

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5

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3

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2

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Solution

The correct option is A $5$
$y = | x - 1 |, y = 0$ and $| x | = 2$
Area of $△^{l e} I a n d I$
$\frac{3 \times 3}{2} + 1 / 2 = 9 / 2 + 1 / 2 = 5 s q u n i t s .$

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y = - | x | + 3, x = 0, y = 0

x = 2,

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y = 4 x^{2}, x = 0

y = 1, y = 4

List-I	List-II
1. Area of region bounded by $y = 2 x - x^{2}$ and $x -$ axis	a. $\frac{1}{3}$
2. Area of the region ${(x, y) : x^{2} \leq y \leq \| x \|}$	b. $\frac{1}{2}$
3. Area bounded by $y = x$ and $y = x^{3}$	c. $\frac{2}{3}$
4. Area bounded by $y = x \| x \|$ , $x$ -axis and $x = - 1, x = 1$	d. $\frac{4}{3}$

1234

List-I	List-II
1. Area of the region bounded by $y = \| 5 sin x \|$ from $x = 0$ to $x = 4 π$ and x-axis	a. 3/2
2. The area bounded by $y =$ cosx in $[0, 2 π]$ and the $X$ -axis	b. $\sqrt{2} - 1$
3. The area bounded by $y = s i n x, y = c o s x$ and the y-axis	c. 4
4. The area bounded by $y = c o s x, y = x + 1, y = 0$	d. 40

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