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Byju's Answer
Standard XII
Mathematics
Axis
The area encl...
Question
The area enclosed between the curve
y
=
log
e
(
x
+
e
)
and the coordinate axes is
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Solution
Required Area
A
=
0
∫
1
−
e
y
d
x
=
0
∫
1
−
e
log
e
(
x
+
e
)
d
x
Put
x
+
e
=
t
⇒
d
x
=
d
t
also when
x
=
1
−
e
,
t
=
1
and when
x
=
0
,
t
=
e
∴
A
=
e
∫
1
log
e
t
d
t
=
[
t
log
e
t
−
t
]
e
1
=
e
−
e
−
0
+
1
=
1
sq. unit
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