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Question

The area enclosed by a PV graph for one thermodynamic cycle of a heat engine is 610 J. The total thermal energy absorbed by the gas in one cycle is 1300 J. Determine the efficiency of the cycle.

A
47%
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B
23%
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C
9.4%
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D
36.8%
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Solution

The correct option is A 47%
Given that, the area enclosed by PV diagram for one thermodynamic cycle of a heat engine is 610 J.
It means, work done W=610 J.
and, thermal energy absorbed by the gas in one cycle is Q=1300 J
Efficiency of heat engine in one cycle
η=Work doneHeat absorbed=WQ=6101300
=0.46947%
Thus, option (a) is the correct answer.

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