The area enclosed by the curves y -sin x - x axis and - x - is in sq units A- 3-2B- 4C- 2D- 8

The correct option is B 4Required area is 2∫_0^π sin x dx=4sq.units ...

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Equation of Normal at a Point (x,y) in Terms of f'(x)

The area encl...

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The area enclosed by the curves y = |sin x|, x axis and $| x | = π$ is (in sq units)

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\frac{3}{2}

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The area enclosed by the curves y = |sin x|, x axis and |x| = $π$ is (in sq units)

y = | s i n x + c o s x |

y = | c o s x - s i n x |

[0, \frac{π}{2}]

y = | x |

y = 1 - | x |

f (x) = sin x, \forall x \in [0, \frac{π}{2}],

f (x) + f (π - x) = 2, \forall x \in (\frac{π}{2}, π]

f (x) = f (2 π - x), \forall x \in (π, 2 π],

y = f (x)

x

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