Question

The area enclosed by the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$ is

• A. $6\pi$
• B. $3\pi$
• C. $\pi$
• D. $9\pi$

Answer 1

The correct option is A $6\pi$

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$
Comparing the given ellipse to this form, $a=3,b=2$
Area of an ellipse is $=\pi ab=\pi \times 3\times 2=6\pi$