The area enclosed by the graph |x-1| + |y-1| = 2 is
Option (d)
The above is the graph of |x| + |y| = 2. Area of the region enclosed = (product of diagonals)/2 = (4*4)/2 = 8.
Now we get |x-1|+|y-1| =2 by shifting the above graph but the area enclosed will remain same as the size and shape is not changing. So enclosed area = 8