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Question

The area enclosed by the graph |x-1| + |y-1| = 2 is

A
2
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B
4
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C
4√2
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D
8
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E
16
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Solution

The correct option is D 8

Option (d)

The above is the graph of |x| + |y| = 2. Area of the region enclosed = (product of diagonals)/2 = (4*4)/2 = 8.

Now we get |x-1|+|y-1| =2 by shifting the above graph but the area enclosed will remain same as the size and shape is not changing. So enclosed area = 8


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