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Question

The area enclosed by the parabolas x=2y2 and x=13y2 is ab, where a,b are co-prime. Then a+b is

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Solution


Point of intersection of the parabolas,
2y2=13y2y=±1x=2

So, the required area is,
=210(13y2)(2y2) dy=210(1y2) dy=2[yy33]10=2×23=43

Hence, a+b=7

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