The area enclosed by the quadrilateral formed by x 2 y 2-9 x 2-25 y 2-225-0 isA- 60 sq-unitsB- 100 sq-unitsC- 30 sq-unitsD- 20 sq-units

The correct option is A 60 sq.units nbsp;x^2y^2 9x^2 25y^2 + 225 = 0 ⇒ x^2 (y^2 9) 25(y^2 9) = 0 ⇒ (y^2 9)(x^2 25) = 0 Hence area closed by the qu ...

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Standard XII

Mathematics

Pair of Lines

The area encl...

Question

The area enclosed by the quadrilateral formed by $x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0$ is

60

sq.units

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100

sq.units

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30

sq.units

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20

sq.units

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Solution

The correct option is A $60$ sq.units
$x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0$
$\Rightarrow x^{2} (y^{2} - 9) - 25 (y^{2} - 9) = 0$
$\Rightarrow (y^{2} - 9) (x^{2} - 25) = 0$

Hence area closed by the quadrilateral $= 10 \times 6 = 60$ sq.units

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The area enclosed by the quadrilateral formed by x2y2−9x2−25y2+225=0 is

The correct option is A 60 sq.units x2y2−9x2−25y2+225=0 ⇒x2(y2−9)−25(y2−9)=0 ⇒(y2−9)(x2−25)=0 Hence area closed by the quadrilateral =10×6=60 sq.units

The area enclosed by the quadrilateral formed by $x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0$ is

The correct option is A $60$ sq.units
$x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0$
$\Rightarrow x^{2} (y^{2} - 9) - 25 (y^{2} - 9) = 0$
$\Rightarrow (y^{2} - 9) (x^{2} - 25) = 0$

Hence area closed by the quadrilateral $= 10 \times 6 = 60$ sq.units