1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Second Derivative Test for Local Maximum
The area in s...
Question
The area (in sq unit) of the region bounded by the curves
2
x
=
y
2
−
1
and
x
=
0
is
A
1
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
B
2
3
Given curve can be rewritten as
y
2
=
2
x
+
1
2
Therefore, required area
=
∫
1
−
1
x
d
y
=
2
∫
1
0
y
2
−
1
2
d
y
=
[
y
3
3
−
y
]
1
0
=
1
3
−
1
=
2
3
sq unit
Suggest Corrections
0
Similar questions
Q.
The area (in square units) of the region bounded by the curves
2
x
=
y
2
−
1
and
x
=
0
is
Q.
Area of the region bounded by the curve
y
=
cos
x
,
x
=
0
,
and
x
=
π
is
Q.
Given
f
(
x
)
=
⎧
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎨
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎩
x
,
0
≤
x
<
1
2
1
2
x
=
1
2
1
−
x
1
2
<
x
<
1
and
g
(
x
)
=
(
x
−
1
2
)
2
,
x
∈
R
. Then the area (in sq. units) of the region bounded by the curves
y
=
f
(
x
)
and
y
=
g
(
x
)
between the lines
2
x
=
1
to
2
x
=
√
3
is:
Q.
The area (in sq. units) of the region bounded by the curves
y
=
2
x
and
y
=
|
x
+
1
|
,
in the first quadrant is :
Q.
The area (in sq. units) of the region bounded by the curves
y
=
2
x
and
y
=
|
x
+
1
|
, in the first quadrant is:
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Second Derivative Test for Local Maximum
MATHEMATICS
Watch in App
Explore more
Second Derivative Test for Local Maximum
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app