The area (in sq. units) bounded by the curves y=√1−x2 and y=x3−x is
A
π2
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B
π6
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C
π4
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D
3π2
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Solution
The correct option is Aπ2
y=x3−x is is an odd function which is symmetric about origin.
So, area bounded by this curve and x− axis in second and fourth quadrant are equal and equal to A1 (say)
Now, according to figure,
Required area = Area of semi-circle above x−axis +A1−A1 =12×π(1)2=π2