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Question

The area (in sq. units) of a quadrilateral whose vertices are A(5,4), B(3,2), C(5,4) and D(7,6) taken in order, is

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Solution

Given vertices are A(5,4),B(3,2),C(5,4) and D(7,6)
So, the area of quadrilateral is
Δ=125357542464Δ=12|22+22+58+58|Δ=80 sq. units

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