Question

The area (in square units) bounded by the curve $y=\sqrt{x},2y=x+3=0$, x-axis, and lying in the first quadrant is

• A. $9$
• B. $36$
• C. $18$
• D. none

Answer 1

The correct option is D none

Finding intersection of $y=\sqrt{x}$ and $2y=x+3$,

$2\sqrt{x}=x+3$

$\Rightarrow 4x=x^2+9+6x$

$\Rightarrow x^2+2x+9$

$D=4-36<0$

$\Rightarrow$ No intersection

Area bounded by these curves is not bounded, hence it years the infinite.