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Question

The area (in square units) of the quadrilateral formed by the two pairs of lines

l2x2−m2y2−n(lx+my)=0

and l2x2−m2y2+n(lx−my)=0 is


A

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B

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C

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D

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Solution

The correct option is A


Given lines are (on factorising)

lx + my = 0, lx - my + n = 0

lx - my = 0, lx + my - n = 0

Area = ∣∣(c1−d1)(c2−d2)(a1b2−a2b1)∣∣=∣∣(0−n)(0+n)(−lm−lm)∣∣=n22|lm|.


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