The area (in square units) of the quadrilateral formed by the two pairs of lines
l2x2−m2y2−n(lx+my)=0
and l2x2−m2y2+n(lx−my)=0 is
Given lines are (on factorising)
lx + my = 0, lx - my + n = 0
lx - my = 0, lx + my - n = 0
Area = ∣∣(c1−d1)(c2−d2)(a1b2−a2b1)∣∣=∣∣(0−n)(0+n)(−lm−lm)∣∣=n22|lm|.