The area in the first quadrant enclosed by the x - axis- the line x-y -3 and the circle x2 - y2 - 4 is

The correct option is D π/3 ...

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Formation of a Differential Equation from a General Solution

The area in t...

Question

The area in the first quadrant enclosed by the x - axis, the line $x = y \sqrt{3}$ and the circle $x^{2} + y^{2} = 4$ is

π

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\frac{π}{2}

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\frac{π}{4}

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\frac{π}{3}

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Solution

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Similar questions

x^{2} + y^{2} = 4

x = \frac{y}{\sqrt{3}}

x = y \sqrt{3}

x^{2} + y^{2} = 4

\sqrt{3} y

x = \sqrt{3} y

x^{2} + y^{2} = 4

x = \sqrt{3}

x

y = \frac{1}{\sqrt{3}} x

x^{2} + y^{2} = 4

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