The area included between the parabolas $y^{2} = 4 x$ and $x^{2} = 4 y$ is

\frac{8}{3}

sq unit

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8

sq unit

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\frac{16}{3}

sq unit

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12

sq unit

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Solution

The correct option is D $\frac{16}{3}$ sq unit
We know that, the area of region bounded by the parabolas $y^{2} = 4 a x$ and $x^{2} = 4 b y$ is $\frac{16}{3} a b$ sq.unit.
Therefore, $y^{2} = 4 a x$ and $x^{2} = 4 y$ is $\frac{16}{3}$ sq.unit.
$(∵ a = 1, b = 1)$

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