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Byju's Answer
Standard XII
Mathematics
Definition of Circle
The area of a...
Question
The area of a circle is doubled when its radius
r
is increased by
n
. Then
r
equals:
A
n
(
√
2
+
1
)
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B
n
(
√
2
−
1
)
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C
h
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D
n
(
2
−
√
2
)
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E
n
π
√
2
+
1
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Solution
The correct option is
B
n
(
√
2
+
1
)
A
=
π
r
2
2
A
=
π
(
r
+
n
)
2
2
π
r
2
=
π
(
r
2
+
n
2
+
2
n
r
)
r
2
=
n
2
(
1
+
2
n
)
r
=
n
(
1
+
√
2
)
Suggest Corrections
0
Similar questions
Q.
If
R
=
cos
2
(
n
−
1
n
)
π
+
cos
2
(
n
−
2
n
)
π
+
⋯
+
cos
2
(
2
π
n
)
+
cos
2
(
π
n
)
, then value of
R
is
Q.
The area of a circle is doubled when its radius
r
is increased by
a
. Therefore, radius
r
equals
Q.
If
C
r
stands for
n
C
r
, then the sum of the series
2
(
n
2
)
!
(
n
2
)
!
n
!
[
C
2
0
−
2
C
2
1
+
3
C
2
2
−
.
.
.
.
+
(
−
1
)
n
(
n
+
1
)
C
2
n
]
where
n
is an even positive integer, is equal to
Q.
Column - I
Column - II
(A)
∑
n
r
=
1
r
.
n
C
r
is equal to
(P)
(
n
+
2
)
.2
n
−
1
(B)
∑
n
+
1
r
=
1
r
.
n
C
r
−
1
is equal to
(Q)
(
n
+
1
)
.
2
n
C
n
(C)
∑
n
r
=
0
(
2
r
+
1
)
.
n
C
r
is equal to
(R)
(
n
+
1
)
.2
n
(D)
∑
n
r
=
0
(
2
r
+
1
)
.
(
n
C
r
)
2
is equal to
(S)
n
.2
n
−
1
Q.
If
(
2
≤
r
≤
n
)
,
then
n
C
r
+
2
⋅
n
C
r
+
1
+
n
C
r
+
2
is equal to
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