The area of a garden is 18/9 sq mi and the dimensions of the nearest garden are 3 mi and 6 mi. What is the total area of the two gardens?

18 sq mi

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22 sq mi

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20 sq mi

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24 sq mi

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Solution

The correct option is C 20 sq mi
Area of the first garden = $\frac{18}{9}$ sq mi

= 2 sq mi

Area of another garden = 3 mi $\times$ 6 mi

= 18 sq mi

Total area = 2 sq mi + 18 sq mi
= 20 sq mi

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The area of a garden is 18/9 sq mi and the dimensions of the nearest garden are 3 mi and 6 mi. What is the total area of the two gardens?

The correct option is C 20 sq miArea of the first garden = 189 sq mi = 2 sq mi Area of another garden = 3 mi × 6 mi = 18 sq mi Total area = 2 sq mi + 18 sq mi = 20 sq mi

The correct option is C 20 sq mi
Area of the first garden = $\frac{18}{9}$ sq mi

= 2 sq mi

Area of another garden = 3 mi $\times$ 6 mi

= 18 sq mi

Total area = 2 sq mi + 18 sq mi
= 20 sq mi