The area of a man's foot is $80 {c m}^{2}$ . How much pressure will the man exert on the ground, while standing, if the weight is $800 N$ ?

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Solution

Area of foot
$A = 80 c m^{2}$
$\Rightarrow A = \frac{80}{10000} m^{2}$

Weight
$F = 800 N$

$Pressure = \frac{w e i g h t}{A r e a}$

$\Rightarrow P = \frac{800}{80 / 10000}$

$\Rightarrow P = 98000$ Pascals.

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The area of a man's foot is 80 cm2. How much pressure will the man exert on the ground, while standing, if the weight is 800 N?

Area of footA=80 cm2⇒A=8010000m2WeightF=800 NPressure=weightArea⇒P=80080/10000⇒P=98000 Pascals.

The area of a man's foot is $80 {c m}^{2}$ . How much pressure will the man exert on the ground, while standing, if the weight is $800 N$ ?

Area of foot
$A = 80 c m^{2}$
$\Rightarrow A = \frac{80}{10000} m^{2}$

Weight
$F = 800 N$

$Pressure = \frac{w e i g h t}{A r e a}$

$\Rightarrow P = \frac{800}{80 / 10000}$

$\Rightarrow P = 98000$ Pascals.